A facile and controllable vacuum-calcination strategy is utilized to convert Co(OH) 2 into oxygen-defective amorphous-crystalline CoO (namely ODAC-CoO) nanosheets. With the carefully controlled crystallinity and oxygen vacancy levels, the optimal ODAC-CoO sample exhibits dramatically enhanced ORR and OER electrocatalytic activities compared

Wakacje kredytowe to jedna form pomocy w obliczu wysokich rat kredytowych, które dotknęły Polaków wskutek podwyższania stóp procentowych. Stosowna ustawa w tej sprawie została opublikowana w Dzienniku Ustaw 14 lipca. W życie wejdzie po dwóch tygodniach, a zatem już w najbliższy piątek (29 lipca). Od tego dnia klienci banków będą mogli składać wnioski o zawieszenie płatności w życie ustawy pod koniec miesiąca sprawia, że klienci płacący raty na początku miesiąca (np. 1 sierpnia) muszą się spieszyć, jeśli chcą zawieszenia płatności najbliższej kredytowe - ile czasu ma bank na potwierdznie wniosku?Warto przy tym pamiętać, że wakacje kredytowe przewidziano jedynie dla osób, które spłacają hipotekę finansującą zakup mieszkania lub domu, w którym mieszkają. Nie ma możliwości uzyskania wsparcia w sytuacji, gdy zaciągnęliśmy kredyt na mieszkanie czy dom, które wynajmujemy innym podkreślała ostatnio minister finansów Magdalena Rzeczkowska, wakacje kredytowe nie są uzależ

Step 4: Substitute Coefficients and Verify Result. Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced. CoCl2 + 2 NaOH = Co (OH)2 + 2 NaCl. Reactants.

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Importantly, because the CO removal rate is not altered, the OH/CO abundance ratio is unaffected when the FUV is turned on, and the transition from the CO-dominated to the OH-dominated regimes still occurs near the H-to-H 2 transition. We discuss OH/CO further in Section 5.3. 5.2 Dependence on ζ/n for fixed Z ′

Franczyzobiorcy decydują się na tworzenie klubów czytelnika. Portal podał, że pierwszy klub czytelnika funkcjonuje już w sieci Carrefour stanowisko dla czytelnika utworzono w jednym ze stołecznych sklepów. Wspomniany serwis przekazał, że książki można wypożyczyć lub wymienić. Jest też szansa na to, by usiąść przy stoliku i poczytać na dwóch sklepach Carrefour Express zabrakło natomiast miejsca na stoliki i krzesła. Regał z książkami ustawiono natomiast na nieczynnym stanowisku kasowym - pomiędzy alkoholem oraz prezerwatywami i gumami do żucia. Omijają zakaz handlu. Jest zapowiedź kontroliPortal zwrócił się do centrali sieci Carrefour w Polsce z zapytaniem prasowym. W odpowiedzi poinformowano, że spośród 700 sklepów franczyzowych, które zrzesza, przeważająca część nie działa w naszych analiz wynika, iż tylko ok. 25 proc. jest otwarta w niedziele "niehandlowe

Step 3: Verify that the equation is balanced. Since there are an equal number of atoms of each element on both sides, the equation is balanced. Co (OH) 3 + H 2 SO 4 = Co (OH)SO 4 + 2 H 2 O. Balance the reaction of Co (OH)3 + H2SO4 = Co (OH)SO4 + H2O using this chemical equation balancer!

EweSia11 zapytał(a) o 21:13 Co oznacza wzór chemiczny O2 (małe dwa) 2O i 3O2 (małe dwa)? 0 ocen | na tak 0% 0 0 Odpowiedz Odpowiedzi 黒猫 odpowiedział(a) o 21:15 O2(małe) - jedna cząsteczka tlenu2O - dwa atomy tlenu3O2(małe) - trzy cząsteczki tlenu 0 0 adusia490 [Pokaż odpowiedź] Uważasz, że znasz lepszą odpowiedź? lub

One mole of Acetic Acid [C2H2(OH)2] and two moles of Dioxygen [O2] react to form two moles of Carbon Dioxide [CO2] and two moles of Water [H2O] Show Chemical Structure Image Reaction Type

SolutionStart with the Carbon. It's really a toss-up between it and the Hydrogen, but you can just ignore the Oxygen off the top, since it is by itself on one side, making it easy to fix at the end. Since you have minimum 6 Carbons on the right, you need at least 6 CO2 to balance the Carbon, as CO2 has only 1 each. 6CO2 + H2O -----> C6H12O6 + O2 The Carbon is balanced, so let's try to balance the Hydrogen now. Since there are 12 Hydrogens on the right, we need 6 H2O to balance, as there are 2 Hydrogens in each. 6CO2 + 6H2O -----> C6H12O6 + O2 Checking both sides again, we see that both sides have the same number of Carbon and Hydrogen, so now let's look at the Oxygen. Counting the left side, we see that there are 6(2) + 6 = 18 Oxygen. However, the right side only has 6 + 2 = 8 Oxygen. Fortunately, the difference of 10 is an even number, so all we need to do is increase the coefficient for O2 until we get 18 on the right side. Since each additional O2 provides 2 additional Oxygen, we will need 10/2=5 ADDITIONAL O2. The new coefficient should be 6, giving: 6CO2+6H2O -----> C6H12O6 + 6O2 Checking both sides, we now see that it is balancedSuggest Corrections0

CdS quantum dots (QDs) and Co(OH)2 were deposited on the surface of TiO2 nanotube arrays (NTAs) by successive ionic layer adsorption and reaction (SIL…

Wpisz reakcję chemiczną w celu jej zbilansowania.: Bilansowanie równania: 2 C2H2 + 5 O2 = 4 CO2 + 2 H2O Typ reakcji: combustionStechiometria reakcjiCzynnik ograniczającyZwiązekWspółczynnikMasa Jednostki: masa molowa - g/mol, masa - o naszej stronie swoim znajomym!Bezpośredni link do tego zbilansowanego równania: Instrukcje dotyczące bilansowania równań chemicznych: Wpisz równanie reakcji chemicznej, a następnie naciśnij przycisk 'Zbilansuj'. Rozwiązanie pojawi się poniżej. Zawsze używaj dużej litery jako pierwszego znaku w nazwie elementu i małej do reszty symbolu pierwiastka. Przykłady: Fe, Au, Co, Br, C, O, N, F. Porównaj: Co - kobalt i CO - tlenek węgla, Aby wprowadzić ładunek ujemny do wykorzystania równań chemicznych użyj znaku {-} lub e Aby wprowadzić jon, wprowadź wartościowość po związku w nawiasach klamrowych: {+3} lub {3 +} lub {3} Przykład: {Fe 3 +} +. I {-} = {Fe 2 +} + I2 grupy niezmienne substytut w związkach chemicznych, aby uniknąć niejasności. Przykładowo C6H5C2H5 + O2 = C6H5OH + CO2 + H2O nie będzie zrównoważony, ale PhC2H5 + O2 = PhOH + CO2 + H2O będzie Określenie stanu skupienia [jak (s) (aq) lub (g)] nie jest wymagane. Jeśli nie wiesz, jakie produkty powstają, wprowadź wyłącznie odczynniki i kliknij 'Zbilansuj'. W wielu przypadkach kompletne równanie będzie sugerowane. Przykłady całkowitych równań reakcji chemicznych do zbilansowania: Fe + Cl2 = FeCl3KMnO4 + HCl = KCl + MnCl2 + H2O + Cl2K4Fe(CN)6 + H2SO4 + H2O = K2SO4 + FeSO4 + (NH4)2SO4 + COC6H5COOH + O2 = CO2 + H2OK4Fe(CN)6 + KMnO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2OCr2O7{-2} + H{+} + {-} = Cr{+3} + H2OS{-2} + I2 = I{-} + SPhCH3 + KMnO4 + H2SO4 = PhCOOH + K2SO4 + MnSO4 + H2OCuSO4*5H2O = CuSO4 + H2Ocalcium hydroxide + carbon dioxide = calcium carbonate + watersulfur + ozone = sulfur dioxide Przykłady reagentów chemicznych równania (zostanie zasugerowane sumaryczne równanie): H2SO4 + K4Fe(CN)6 + KMnO4Ca(OH)2 + H3PO4Na2S2O3 + I2C8H18 + O2hydrogen + oxygenpropane + oxygen Powiązane narzędzia chemiczne: Kalkulator Masy Molowej Przelicznik pH równania chemiczne dziś bilansowane Wyraź opinię o działaniu naszej aplikacji.

HCOOH + 2Cu (OH) 2 Cu 2 O + CO 2 + 3H 2 O. 2. Điều kiện phản ứng xảy ra. 3. Hiện tượng phản ứng xảy ra khi cho HCOOH tác dụng Cu (OH)2. Dung dịch tạo kết tủa Cu (OH) 2 sau khi cho andehit fomic đun nóng nhẹ vào dung dịch tạo kết tủa đỏ gạch Cu 2 O. 4. Bài tập vận dụng liên quan. Câu 1. Cobalt(II) hydroxide react with oxygen 4Co(OH)2 + O2 4CoO(OH) + 2H2O [ Check the balance ] Cobalt(II) hydroxide react with oxygen to produce cobalt metahydroxide and water. This reaction takes place at a temperature near 100°C and an overpressure. Find another reaction Thermodynamic properties of substances The solubility of the substances Periodic table of elements Picture of reaction: Сoding to search: 4 CoOH2 + O2 cnd [ temp ] = 4 CoOOH + 2 H2O Add / Edited: / Evaluation of information: out of 5 / number of votes: 1 Please register to post comments

C2H5OH O2: Phản ứng đốt cháy rượu etylic. 1. Phương trình phản ứng C2H5OH ra CO2. C2H5OH＋3O2 2CO2＋3H2O. 2. Điều kiện xác định phản ứng đốt cháy rượu etylic. 3. Tính chất hóa học của Etylic. 3.1 Etylic C2H5OH phản ứng với oxi.

Equation Result #1 Click to see further details and calculate weight / mol >> O2 + 4Co(OH)2 → 2H2O + 4CoO(OH) oxygen Cobalt(II) hydroxide; Cobalt hydroxide; Cobalt(II)dihydoxide water Cobalt hydroxide oxide 1 4 2 4 Hệ số Nguyên - Phân tử khối (g/mol) Số mol Khối lượng (g) Advertisement Further information about equation O2 + 4Co(OH)2 → 2H2O + 4CoO(OH) What is reaction condition of O2 (oxygen) reacts with Co(OH)2 (Cobalt(II) hydroxide; Cobalt hydroxide; Cobalt(II)dihydoxide) ? Temperature: 100°C Pressure: pressure condition Explanation: The ideal environmental conditions for a reaction, such as temperature, pressure, catalysts, and solvent. Catalysts are substances that speed up the pace (velocity) of a chemical reaction without being consumed or becoming part of the end product. Catalysts have no effect on equilibrium situations. How reactions can happened and produce H2O (water) and CoO(OH) (Cobalt hydroxide oxide) ? Phenomenon after O2 (oxygen) reacts with Co(OH)2 (Cobalt(II) hydroxide; Cobalt hydroxide; Cobalt(II)dihydoxide) This equation does not have any specific information about phenomenon. In this case, you just need to observe to see if product substance CoO(OH) (Cobalt hydroxide oxide), appearing at the end of the reaction. Or if any of the following reactant substances Co(OH)2 (Cobalt(II) hydroxide; Cobalt hydroxide; Cobalt(II)dihydoxide), disappearing What are other important informations you should know about reaction We no further information about this chemical reactions. Categories of equation Click to see further details and calculate weight / mol >> Further questions related to chemical reactions O2 + 4Co(OH)2 → 2H2O + 4CoO(OH) Questions related to reactant O2 (oxygen) What are the chemical and physical characteristic of O2 (oxygen)? What are the chemical reactions that have O2 (oxygen) as reactant? Questions related to reactant Co(OH)2 (Cobalt(II) hydroxide; Cobalt hydroxide; Cobalt(II)dihydoxide) What are the chemical and physical characteristic of Co(OH)2 (Cobalt(II) hydroxide; Cobalt hydroxide; Cobalt(II)dihydoxide)? What are the chemical reactions that have Co(OH)2 (Cobalt(II) hydroxide; Cobalt hydroxide; Cobalt(II)dihydoxide) as reactant?Questions related to product H2O (water) What are the chemical and physical characteristic of H2O (Cobalt(II) hydroxide; Cobalt hydroxide; Cobalt(II)dihydoxide)? What are the chemical reactions that have H2O (water) as product?Questions related to product CoO(OH) (Cobalt hydroxide oxide) What are the chemical and physical characteristic of CoO(OH) (Cobalt(II) hydroxide; Cobalt hydroxide; Cobalt(II)dihydoxide)? What are the chemical reactions that have CoO(OH) (Cobalt hydroxide oxide) as product?

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Balance the reaction of C2H4CO(OH)2 + O2 = CO2 + H2O using this chemical equation balancer! ChemicalAid. ChemicalAid; ZeptoMath; C 2 H 4 CO(OH) 2 + 3 O 2 → 3 CO

Carbon monoxide react with oxygen 2CO + O2 → 2CO2 [ Check the balance ] Carbon monoxide react with oxygen to produce carbon dioxide. The reaction proceeds at room temperature. In this reaction, the catalyst is can be manganese(IV) oxide or copper oxide. Find another reaction Thermodynamic properties of substances The solubility of the substances Periodic table of elements Picture of reaction: Сoding to search: 2 CO + O2 = 2 CO2 Add / Edited: / Evaluation of information: out of 5 / number of votes: 2 Please register to post comments

^{There are two main peaks at 780.45 eV and 796.65 eV with a spin-energy separation of 16.2 eV corresponding to Co 2p 2/3 and Co 2p 1/3 of Co(OH) 2 , respectively [24,38].}

Zadanie RoziX2006Co to jest O2, H2 i CO2? Mógłby mi ktoś pomóc? W pracy domowej z chemii musze zapisać w zeszycie co to jest O2, H2 i CO2... pomożecie? SobSob Tlen, wodór i dwutlenek węgla. Wystarczy wpisać w internecie. o 19:59 JohnyP41 O2 - tlenH2 - wodórCO2 - dwutlenek węgla o 21:01 pepeg Jest to zapis cząsteczkowy (wzory sumaryczne) pierwiastków:O2 tlenu / ilościowo cząsteczki tlenu,H2 wodoru / ilościowo cząsteczki wodoru,i związku chemicznego:CO2 tlenku węgla (IV) = ditlenku węgla / ilościowo cząsteczki tlenku węgla (IV) = ditlenku węgla o 06:54 Monoaminooksydaza To są podstawy podstaw. O2 - tlen cząsteczkowy,H2 - wodór cząsteczkowy,CO2 - dwutlenek węgla. o 17:23

Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F. Ionic charges are not yet supported and will be ignored. Replace immutable groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2

covalt Posty: 58 Rejestracja: 3 mar 2011, o 10:00 Jak utlenia się Mn(OH)2 ? Witam. Tak jak w tytule - prosiłbym o pomoc w reakcji utleniania się wodorotlenku manganu (II) z tlenem. W skrypcie mam podane dwie różne reakcje i nie wiem która jest właściwa: 4Mn(OH)2 + O2 2Mn2O3 + 4H2O i 2Mn(OH)2 + O2 2MnO(OH)2 Jak rozumiem związki te są osadami i mają kolor brunatny ? acotusiewpisuje Posty: 15 Rejestracja: 9 lis 2011, o 09:31 Re: Jak utlenia się Mn(OH)2 ? Post autor: acotusiewpisuje » 9 lis 2011, o 09:41 2Mn(OH)2 + O2 → 2 MnO2·H2O Wodorotlenek manganu utlenia się dając uwodniony tlenek Manganu (IV). Mn(OH)2 - biały MnO2 - brunatnoczarny proszek Mn2O3 - czarny MnO(OH)2 chyba jest brunatny, ale ręki nie dam uciąć eszel Posty: 280 Rejestracja: 16 paź 2009, o 22:36 Re: Jak utlenia się Mn(OH)2 ? Post autor: eszel » 9 lis 2011, o 22:32 zapisów reakcji utleniania wodorotlenku manganu jest kilka (barwa jest na 100% brunatna) \(1) 2Mn(OH)_{2}+O_{2} ightarrow 2MnO_{2}+2H_{2}O 2) 2Mn(OH)_{2}+O_{2} ightarrow 2H_{2}MnO_{3} H_{2}MnO_{3}+Mn(OH)_{2} ightarrow MnMnO_{3}+2H_{2}O 3) 4Mn(OH)_{2}+O_{2} ightarrow 4MnO(OH)+2H_{2}O 4MnO(OH)+O{2} ightarrow 4MnO_{2}+2H_{2}O\) dla mnie ta ostatnia wersja jest najfajniejsza, chodzi tu o to, że Mn utlenia sie z II na III i potem na IV stopień, wszystkie zapisy są ok Burza Posty: 57 Rejestracja: 18 kwie 2012, o 20:41 Re: Jak utlenia się Mn(OH)2 ? Post autor: Burza » 18 kwie 2012, o 20:44 mam takie pytanie co do tej reakcji : 2Mn(OH)2 + O2 2MnO(OH)2 czy może one przebiec w taki sposób? Mn(OH)2 + Ag2O MnO(OH)2 + 2 Ag Kto jest online Użytkownicy przeglądający to forum: Obecnie na forum nie ma żadnego zarejestrowanego użytkownika i 0 gości

Step 3: Verify that the equation is balanced. Since there are an equal number of atoms of each element on both sides, the equation is balanced. 2 (CH 2 OH) 2 CHOH + 7 O 2 = 6 CO 2 + 8 H 2 O. Balance the reaction of (CH2OH)2CHOH + O2 = CO2 + H2O using this chemical equation balancer!

Access through your institutionHighlights•CeO2-Co(OH)2 was prepared through one-step electro-deposition strategy.•The content of oxygen vacancies increased by the introduction of CeO2 into Co(OH)2.•The electron environment of Co and Ce can be tuned by adjusting Co to Ce ratio.•The optimized CeO2-Co(OH)2 was active for HER and obtain highly active electrocatalyst for the whole electrochemical water splitting is of importance to generate hydrogen. Co(OH)2 is used as electrocatalyst towards OER, however, the performance can be improved further. Usually, to construct the interface and adjust the electronic environment of electrocatalysts are regarded as powerful ways to improve the activity. Herein, CeO2-Co(OH)2 sheets supported on copper foam (CF) are fabricated by electrodeposition method. The morphology and the electron structure of metals are adjusted by changing the molar ratio of Co to Ce, thus, resulting in different electrocatalytic activity. The optimal hybrids of CeO2-Co(OH)2 exhibits lower overpotentials of 188, 269 mV to reach 10 mA cm−2 towards HER and OER, respectively, and good stability. Notably, it is found that the electroactivity is extremely superior to that of bare CF as well as the counterparts in the literature. Also, we try to employ M(OH)2 (M = Fe, Ni) to substitute Co(OH)2 to investigate the effect of species of hydroxides on the electron interaction between CeO2 and hydroxides, the XPS results indicate that Ce and Co shows stronger electron interaction compared to other two control hydroxides. As electrocatalysts for alkaline full water splitting, CeO2-Co(OH)2 requires a cell voltage of V to drive 10 mA cm−2. Experimental results prove the advantages of the electron engineering and morphology double hydroxidesOxygen evolution reactionHydrogen evolution reactionElectrocatalysisCited by (0)View full text© 2022 Elsevier All rights reserved.

Calcule o reagente limitante. Equação química (CH3OH + O2 = CO2 + H2O) 🛠️. Equação Equilíbrio . Use letras maiúsculas para o primeiro carácter no elemento e minúsculas para o segundo carácter. Exemplos: Fe, Au, Co, Br, C, O, N, F. Cargas iônicas ainda não são suportados e serão ignorados. Substitua grupos imutáveis em

. 2022 Jun 7;51(22):8832-8839. doi: Affiliations PMID: 35621026 DOI: Ir-Doped Co(OH) 2 nanosheets as an efficient electrocatalyst for the oxygen evolution reaction Yihao Gao et al. Dalton Trans. 2022. Abstract In recent years, Co-based metal-organic frameworks (Co-MOFs) have received significant research interest because of their large specific surface area, high porosity, tunable structure and topological flexibility. However, their comparatively weak electrical conductivity and inferior stability drastically restrict the application of Co-MOFs in the synthesis of electrocatalysts. In this study, ZIF-67 was grown on nickel foam by a room temperature soaking method, and then Ir-Co(OH)2@ZIF-67/NF was assembled by a hydrothermal method. The prepared Ir-Co(OH)2@ZIF-67/NF nanosheets exhibit remarkable conductivity, larger electrochemical active surface area and wider electron transport channels. Only ultralow overpotentials of 198 mV, 263 mV, and 300 mV were needed for Ir-Co(OH)2@ZIF-67/NF to reach the current densities of 10 mA cm-2, 50 mA cm-2, 100 mA cm-2, meanwhile, no obvious degradation of the current density at 10 mA cm-2 was observed for about 16 h. This work may provide a promising strategy for developing high-performance MOF-derived materials as electrocatalysts for the OER under alkaline conditions. Similar articles Assembly of ZIF-67 nanoparticles and in situ grown Cu(OH)2 nanowires serves as an effective electrocatalyst for oxygen evolution. Ye L, Zhang Y, Wang L, Zhao L, Gong Y. Ye L, et al. Dalton Trans. 2021 Jun 1;50(21):7256-7264. doi: Dalton Trans. 2021. PMID: 33960361 An ingeniously assembled metal-organic framework on the surface of FeMn co-doped Ni(OH)2 as a high-efficiency electrocatalyst for the oxygen evolution reaction. Ye L , Zhang Y , Zhang M , Gong Y . Ye L , et al. Dalton Trans. 2021 Sep 14;50(34):11775-11782. doi: Epub 2021 Aug 5. Dalton Trans. 2021. PMID: 34351336 Formation of carnation-like ZIF-9 nanostructure to achieve superior electrocatalytic oxygen evolution. Li T, Xu Z, Lin S. Li T, et al. Nanotechnology. 2022 Feb 21;33(20). doi: Nanotechnology. 2022. PMID: 35086070 Three-Dimensional N-Doped Carbon Nanotube Frameworks on Ni Foam Derived from a Metal-Organic Framework as a Bifunctional Electrocatalyst for Overall Water Splitting. Yuan Q, Yu Y, Gong Y, Bi X. Yuan Q, et al. ACS Appl Mater Interfaces. 2020 Jan 22;12(3):3592-3602. doi: Epub 2020 Jan 7. ACS Appl Mater Interfaces. 2020. PMID: 31858792 Uniquely integrated Fe-doped Ni(OH)2 nanosheets for highly efficient oxygen and hydrogen evolution reactions. Ren JT, Yuan GG, Weng CC, Chen L, Yuan ZY. Ren JT, et al. Nanoscale. 2018 Jun 14;10(22):10620-10628. doi: Epub 2018 May 30. Nanoscale. 2018. PMID: 29845142 LinkOut - more resources Full Text Sources Royal Society of Chemistry

1. Introduction The solid structure of cobalt(II) carbonate hydroxide [Co 2 CO 3 (OH) 2] is important for technological and environmental reasons.It is commonly used as a precursor in the synthesis of cobalt oxides (Li et al., 2006 , 2012 ; Xie et al., 2010 ; Xu & Zeng, 2003 ), which have a wide range of technological applications as petroleum catalysts, magnetic materials, semiconductors

You follow a systematic procedure to balance the equation. Start with the unbalanced equation: #"CH"_3"OH" + "O"_2 → "CO"_2 + "H"_2"O"# A method that often works is first to balance everything other than #"O"# and #"H"#, then balance #"O"#, and finally balance #"H"#. Another useful procedure is to start with what looks like the most complicated formula. The most complicated formula looks like #"CH"_3"OH"#. We put a 1 in front of it to remind ourselves that the number is now fixed. We start with #color(red)(1)"CH"_3"OH" + "O"_2 → "CO"_2 + "H"_2"O"# Balance #"C"#: We have #"1 C"# on the left, so we need #"1 C"# on the right. We put a 1 in front of the #"CO"_2#. #color(red)(1)"CH"_3"OH" + "O"_2 → color(blue)(1)"CO"_2 + "H"_2"O"# Balance #"H"#: We can't balance #"O"# because we have two oxygen-containing molecules without coefficients. ∴ Let's balance #"H"# instead. We have #"4 H"# on the left, so we need #"4 H"# on the right. There are already #"2 H"# atoms on the right. We must put a 2 in front of the #"H"_2"O"#. #color(red)(1)"CH"_3"OH" + "O"_2 → color(blue)(1)"CO"_2 + color(orange)(2)"H"_2"O"# Balance #"O"#: We have fixed #"4 O"# on the right and #"1 O"# on the left. We need #"3 O"# on the left. Uh, oh! Fractions! We start over, this time doubling all the coefficients. #color(red)(2)"CH"_3"OH" + "O"_2 → color(blue)(2)"CO"_2 + color(orange)(4)"H"_2"O"# Now we can balance #"O"# by putting a 3 in front of #"O"_2# #color(red)(2)"CH"_3"OH" + color(purple)(3)"O"_2 → color(blue)(2)"CO"_2 + color(orange)(4)"H"_2"O"# Every formula now has a coefficient. We should have a balanced equation. Let's check. #"Atom" color(white)(m)"lhs"color(white)(m)"rhs"# #color(white)(m)"C"color(white)(mml)2color(white)(mm)2# #color(white)(m)"H"color(white)(mml)8color(white)(mm)8# #color(white)(m)"O"color(white)(mml)8color(white)(mm)8# All atoms balance. The balanced equation is #2"CH"_3"OH" + 3"O"_2 → 2"CO"_2 + 4"H"_2"O"# .